In △ABC (not isosceles) CH, CL and CM are respectively height, bisector and median. Show that ∠ACB=90 degrees if and only if ∠HCL=∠MCL.
I think that I have to show that △MCB (or △ACM) is isosceles, but I can't figure it out. I will be very grateful if you help me.
Show that a triangle is right angled
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Re: Show that a triangle is right angled
Height of what, bisector of what, and median of what?
Try drawing a picture.
Is this homework?
Try drawing a picture.
Is this homework?
wee free kings
Re: Show that a triangle is right angled
Assuming H, L, and M are on segment AB (which is the only way to make sense of the question), ask yourself the following questions:
1: Sum of ∠A, ∠B, and ∠C is.... what?
2: What does that imply if (as desired) ∠C = 90 degrees?
3: Considering all the angles at C (except ∠ACB)... what is their sum?
4: Consider the consequences of the congruent angles of the two triangles you suspect must be isosceles.
That should get you going.
Jose
1: Sum of ∠A, ∠B, and ∠C is.... what?
2: What does that imply if (as desired) ∠C = 90 degrees?
3: Considering all the angles at C (except ∠ACB)... what is their sum?
4: Consider the consequences of the congruent angles of the two triangles you suspect must be isosceles.
That should get you going.
Jose
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