## finite field question

For the discussion of math. Duh.

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qubits1
Posts: 1
Joined: Tue Oct 28, 2008 8:39 pm UTC

### finite field question

Wikipedia article on Finite Field Arithmetic says addition and subtraction are equivalent operations a+b=a^b and a-b=a^b.
I'm trying to implement multiplication and division in GF(256) by using the identity a*b=antilog(log(a)+log(b)) mod 255 and a/b =anitlog(log(a)-log(b)) mod 255
Does this mean that the addition and subtraction in the multiplication and division identities above are equal to a^b?
Wouldn't this give you the same result for multiplication and division?

jaap
Posts: 2094
Joined: Fri Jul 06, 2007 7:06 am UTC
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### Re: finite field question

You seem to be assuming that log in this context is a function from GF(2n) to GF(2n), but it is not.
The multiplicative group of GF(2n) is cyclic of order 2n-1. If g is a generator of that group, then you are multiplying two elements a=ge and b=gf as a*b = gegf = ge+f = c. The addition of these exponents is not done in the field GF(2^n) itself but in (an additive version of) this cyclic group. So log is a function from GF(2n) to Z_(2n-1).

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